Xuan spent
35 of her money on 4 highlighters and 7 foolscaps. The cost of one foolscap was twice the cost of one highlighter. She bought some more foolscaps with
13 of her remaining money. How many foolscaps did Xuan buy altogether?
4 highlighters and
7 foolscaps |
Remaining amount |
| 3x3 |
2x3 |
| |
More foolscaps |
Left |
| |
1x2 |
2x2 |
| 9 p |
2 p |
4 p |
Cost of 1 highlighter = 1 u
Cost of 1 foolscap = 2 u
Cost of 4 highlighters = 4 x 1 u = 4 u
Cost of 7 foolscaps = 7 x 2 u = 14 u
Total cost of 4 highlighters and 7 foolscaps
= 4 u + 14 u
= 18 u
9 p = 18 u
1 p = 18 ÷ 9 = 2 u
Amount that Xuan used to buy more foolscaps
= 2 p
= 2 x 2 u
= 4 u
Number of more foolscaps that Xuan bought
= 4 u ÷ 2 u
= 2
Total number of foolscaps that Xuan bought
= 7 + 2
= 9
Answer(s): 9
