Abi bought some pens. She gave
14 of the pens to her brother and sold
35 of the remaining pens. After that, she bought another 98 pens and had the same number of pens that she bought at first. How many pens did Abi buy at first?
| Her brother |
Remaining pens |
Bought pens |
Total |
1x5 =
5 u |
3x5 =
15 u |
|
4x5 =
20 u |
| |
Sold |
Left |
|
|
| |
3x3 |
2x3 |
|
|
| 5 u |
9 u |
6 u |
98 |
|
The remaining number of pens before Abi bought another 98 pens is repeated. Make the remaining number of pens the same. LCM of 3 and 5 is 15.
Total number of pens at first = 20 u
Number of pens that Abi had left and bought after that = 6 u + 98
20 u = 6 u + 98
20 u - 6 u = 98
14 u = 98
1 u = 98 ÷ 14 = 7
Total number of pens at first
= 20 u
= 20 x 7
= 140
Answer(s): 140
