Pamela bought some coins. She gave
14 of the coins to her cousin and sold
35 of the remaining coins. After that, she bought another 154 coins and had the same number of coins that she bought at first. How many coins did Pamela buy at first?
| Her cousin |
Remaining coins |
Bought coins |
Total |
1x5 =
5 u |
3x5 =
15 u |
|
4x5 =
20 u |
| |
Sold |
Left |
|
|
| |
3x3 |
2x3 |
|
|
| 5 u |
9 u |
6 u |
154 |
|
The remaining number of coins before Pamela bought another 154 coins is repeated. Make the remaining number of coins the same. LCM of 3 and 5 is 15.
Total number of coins at first = 20 u
Number of coins that Pamela had left and bought after that = 6 u + 154
20 u = 6 u + 154
20 u - 6 u = 154
14 u = 154
1 u = 154 ÷ 14 = 11
Total number of coins at first
= 20 u
= 20 x 11
= 220
Answer(s): 220
