Hilda bought some marbles. She gave
14 of the marbles to her brother and sold
25 of the remaining marbles. After that, she bought another 121 marbles and had the same number of marbles that she bought at first. How many marbles did Hilda buy at first?
| Her brother |
Remaining marbles |
Bought marbles |
Total |
1x5 =
5 u |
3x5 =
15 u |
|
4x5 =
20 u |
| |
Sold |
Left |
|
|
| |
2x3 |
3x3 |
|
|
| 5 u |
6 u |
9 u |
121 |
|
The remaining number of marbles before Hilda bought another 121 marbles is repeated. Make the remaining number of marbles the same. LCM of 3 and 5 is 15.
Total number of marbles at first = 20 u
Number of marbles that Hilda had left and bought after that = 9 u + 121
20 u = 9 u + 121
20 u - 9 u = 121
11 u = 121
1 u = 121 ÷ 11 = 11
Total number of marbles at first
= 20 u
= 20 x 11
= 220
Answer(s): 220
