Sabrina bought some coins. She gave
14 of the coins to her cousin and sold
35 of the remaining coins. After that, she bought another 70 coins and had the same number of coins that she bought at first. How many coins did Sabrina buy at first?
| Her cousin |
Remaining coins |
Bought coins |
Total |
1x5 =
5 u |
3x5 =
15 u |
|
4x5 =
20 u |
| |
Sold |
Left |
|
|
| |
3x3 |
2x3 |
|
|
| 5 u |
9 u |
6 u |
70 |
|
The remaining number of coins before Sabrina bought another 70 coins is repeated. Make the remaining number of coins the same. LCM of 3 and 5 is 15.
Total number of coins at first = 20 u
Number of coins that Sabrina had left and bought after that = 6 u + 70
20 u = 6 u + 70
20 u - 6 u = 70
14 u = 70
1 u = 70 ÷ 14 = 5
Total number of coins at first
= 20 u
= 20 x 5
= 100
Answer(s): 100
