Marion bought some erasers. She gave
17 of the erasers to her brother and sold
34 of the remaining erasers. After that, she bought another 110 erasers and had the same number of erasers that she bought at first. How many erasers did Marion buy at first?
| Her brother |
Remaining erasers |
Bought erasers |
Total |
1x2 =
2 u |
6x2 =
12 u |
|
7x2 =
14 u |
| |
Sold |
Left |
|
|
| |
3x3 |
1x3 |
|
|
| 2 u |
9 u |
3 u |
110 |
|
The remaining number of erasers before Marion bought another 110 erasers is repeated. Make the remaining number of erasers the same. LCM of 6 and 4 is 12.
Total number of erasers at first = 14 u
Number of erasers that Marion had left and bought after that = 3 u + 110
14 u = 3 u + 110
14 u - 3 u = 110
11 u = 110
1 u = 110 ÷ 11 = 10
Total number of erasers at first
= 14 u
= 14 x 10
= 140
Answer(s): 140
