Jane bought some pens. She gave
14 of the pens to her brother and sold
25 of the remaining pens. After that, she bought another 22 pens and had the same number of pens that she bought at first. How many pens did Jane buy at first?
| Her brother |
Remaining pens |
Bought pens |
Total |
1x5 =
5 u |
3x5 =
15 u |
|
4x5 =
20 u |
| |
Sold |
Left |
|
|
| |
2x3 |
3x3 |
|
|
| 5 u |
6 u |
9 u |
22 |
|
The remaining number of pens before Jane bought another 22 pens is repeated. Make the remaining number of pens the same. LCM of 3 and 5 is 15.
Total number of pens at first = 20 u
Number of pens that Jane had left and bought after that = 9 u + 22
20 u = 9 u + 22
20 u - 9 u = 22
11 u = 22
1 u = 22 ÷ 11 = 2
Total number of pens at first
= 20 u
= 20 x 2
= 40
Answer(s): 40
