Xylia bought some erasers. She gave
14 of the erasers to her brother and sold
25 of the remaining erasers. After that, she bought another 33 erasers and had the same number of erasers that she bought at first. How many erasers did Xylia buy at first?
Her brother |
Remaining erasers |
Bought erasers |
Total |
1x5 = 5 u |
3x5 = 15 u |
|
4x5 = 20 u |
|
Sold |
Left |
|
|
|
2x3 |
3x3 |
|
|
5 u |
6 u |
9 u |
33 |
|
The remaining number of erasers before Xylia bought another 33 erasers is repeated. Make the remaining number of erasers the same. LCM of 3 and 5 is 15.
Total number of erasers at first = 20 u
Number of erasers that Xylia had left and bought after that = 9 u + 33
20 u = 9 u + 33
20 u - 9 u = 33
11 u = 33
1 u = 33 ÷ 11 = 3
Total number of erasers at first
= 20 u
= 20 x 3
= 60
Answer(s): 60