Vanessa bought some coins. She gave
13 of the coins to her brother and sold
35 of the remaining coins. After that, she bought another 88 coins and had the same number of coins that she bought at first. How many coins did Vanessa buy at first?
| Her brother |
Remaining coins |
Bought coins |
Total |
1x5 =
5 u |
2x5 =
10 u |
|
3x5 =
15 u |
| |
Sold |
Left |
|
|
| |
3x2 |
2x2 |
|
|
| 5 u |
6 u |
4 u |
88 |
|
The remaining number of coins before Vanessa bought another 88 coins is repeated. Make the remaining number of coins the same. LCM of 2 and 5 is 10.
Total number of coins at first = 15 u
Number of coins that Vanessa had left and bought after that = 4 u + 88
15 u = 4 u + 88
15 u - 4 u = 88
11 u = 88
1 u = 88 ÷ 11 = 8
Total number of coins at first
= 15 u
= 15 x 8
= 120
Answer(s): 120
