Xylia bought some beads. She gave
13 of the beads to her sister and sold
25 of the remaining beads. After that, she bought another 90 beads and had the same number of beads that she bought at first. How many beads did Xylia buy at first?
| Her sister |
Remaining beads |
Bought beads |
Total |
1x5 =
5 u |
2x5 =
10 u |
|
3x5 =
15 u |
| |
Sold |
Left |
|
|
| |
2x2 |
3x2 |
|
|
| 5 u |
4 u |
6 u |
90 |
|
The remaining number of beads before Xylia bought another 90 beads is repeated. Make the remaining number of beads the same. LCM of 2 and 5 is 10.
Total number of beads at first = 15 u
Number of beads that Xylia had left and bought after that = 6 u + 90
15 u = 6 u + 90
15 u - 6 u = 90
9 u = 90
1 u = 90 ÷ 9 = 10
Total number of beads at first
= 15 u
= 15 x 10
= 150
Answer(s): 150
