Hilda bought some beads. She gave
15 of the beads to her sister and sold
35 of the remaining beads. After that, she bought another 51 beads and had the same number of beads that she bought at first. How many beads did Hilda buy at first?
| Her sister |
Remaining beads |
Bought beads |
Total |
1x5 =
5 u |
4x5 =
20 u |
|
5x5 =
25 u |
| |
Sold |
Left |
|
|
| |
3x4 |
2x4 |
|
|
| 5 u |
12 u |
8 u |
51 |
|
The remaining number of beads before Hilda bought another 51 beads is repeated. Make the remaining number of beads the same. LCM of 4 and 5 is 20.
Total number of beads at first = 25 u
Number of beads that Hilda had left and bought after that = 8 u + 51
25 u = 8 u + 51
25 u - 8 u = 51
17 u = 51
1 u = 51 ÷ 17 = 3
Total number of beads at first
= 25 u
= 25 x 3
= 75
Answer(s): 75
