Jade bought some beads. She gave
15 of the beads to her sister and sold
56 of the remaining beads. After that, she bought another 156 beads and had the same number of beads that she bought at first. How many beads did Jade buy at first?
| Her sister |
Remaining beads |
Bought beads |
Total |
1x3 =
3 u |
4x3 =
12 u |
|
5x3 =
15 u |
| |
Sold |
Left |
|
|
| |
5x2 |
1x2 |
|
|
| 3 u |
10 u |
2 u |
156 |
|
The remaining number of beads before Jade bought another 156 beads is repeated. Make the remaining number of beads the same. LCM of 4 and 6 is 12.
Total number of beads at first = 15 u
Number of beads that Jade had left and bought after that = 2 u + 156
15 u = 2 u + 156
15 u - 2 u = 156
13 u = 156
1 u = 156 ÷ 13 = 12
Total number of beads at first
= 15 u
= 15 x 12
= 180
Answer(s): 180
