Cindy bought some beads. She gave
13 of the beads to her cousin and sold
35 of the remaining beads. After that, she bought another 99 beads and had the same number of beads that she bought at first. How many beads did Cindy buy at first?
| Her cousin |
Remaining beads |
Bought beads |
Total |
1x5 =
5 u |
2x5 =
10 u |
|
3x5 =
15 u |
| |
Sold |
Left |
|
|
| |
3x2 |
2x2 |
|
|
| 5 u |
6 u |
4 u |
99 |
|
The remaining number of beads before Cindy bought another 99 beads is repeated. Make the remaining number of beads the same. LCM of 2 and 5 is 10.
Total number of beads at first = 15 u
Number of beads that Cindy had left and bought after that = 4 u + 99
15 u = 4 u + 99
15 u - 4 u = 99
11 u = 99
1 u = 99 ÷ 11 = 9
Total number of beads at first
= 15 u
= 15 x 9
= 135
Answer(s): 135
