Ken spent 18 of his money on balloons, 15 of the remaining money on a swiss roll and $126 on drinks. He had 14 of his money. How much money did he have at first?
| Balloons |
Remaining amount |
Total |
| 1x5 |
7x5 |
8x5 |
| |
Swiss Roll |
Drinks |
Left |
|
| |
1x7 |
4x7 |
|
| 5 u |
7 u |
28 u |
40 u |
Fraction of the amount that Ken had left after spending on balloons
= 1 -
18 =
78 Fraction of the remaining amount that Ken had left after spending on a swiss roll
= 1 -
15 =
45 The remaining amount is the combined repeated identity. Make the remaining amount the same. LCM of 7 and 5 is 35.
Amount that Ken had left
=
14 x 40 u
= 10 u
Amount that Ken spent on drinks
= 28 u - 10 u
= 18 u
18 u = 126
1 u = 126 ÷ 18 = 7
Total amount that Ken had at first
= 40 u
= 40 x 7
= $280
Answer(s): $280
