Xavier spent 16 of his money on balloons, 16 of the remaining money on a pie and $65 on drinks. He had 13 of his money. How much money did he have at first?
Balloons |
Remaining amount |
Total |
1x6 |
5x6 |
6x6 |
|
Pie |
Drinks |
Left |
|
|
1x5 |
5x5 |
|
6 u |
5 u |
25 u |
36 u |
Fraction of the amount that Xavier had left after spending on balloons
= 1 -
16 =
56 Fraction of the remaining amount that Xavier had left after spending on a pie
= 1 -
16 =
56 The remaining amount is the combined repeated identity. Make the remaining amount the same. LCM of 5 and 6 is 30.
Amount that Xavier had left
=
13 x 36 u
= 12 u
Amount that Xavier spent on drinks
= 25 u - 12 u
= 13 u
13 u = 65
1 u = 65 ÷ 13 = 5
Total amount that Xavier had at first
= 36 u
= 36 x 5
= $180
Answer(s): $180