Ken spent 16 of his money on balloons, 16 of the remaining money on a swiss roll and $32 on drinks. He had 14 of his money. How much money did he have at first?
Balloons |
Remaining amount |
Total |
1x6 |
5x6 |
6x6 |
|
Swiss Roll |
Drinks |
Left |
|
|
1x5 |
5x5 |
|
6 u |
5 u |
25 u |
36 u |
Fraction of the amount that Ken had left after spending on balloons
= 1 -
16 =
56 Fraction of the remaining amount that Ken had left after spending on a swiss roll
= 1 -
16 =
56 The remaining amount is the combined repeated identity. Make the remaining amount the same. LCM of 5 and 6 is 30.
Amount that Ken had left
=
14 x 36 u
= 9 u
Amount that Ken spent on drinks
= 25 u - 9 u
= 16 u
16 u = 32
1 u = 32 ÷ 16 = 2
Total amount that Ken had at first
= 36 u
= 36 x 2
= $72
Answer(s): $72