Bobby spent 18 of his money on drinks, 16 of the remaining money on a pie and $138 on balloons. He had 14 of his money. How much money did he have at first?
| Drinks |
Remaining amount |
Total |
| 1x6 |
7x6 |
8x6 |
| |
Pie |
Balloons |
Left |
|
| |
1x7 |
5x7 |
|
| 6 u |
7 u |
35 u |
48 u |
Fraction of the amount that Bobby had left after spending on drinks
= 1 -
18 =
78 Fraction of the remaining amount that Bobby had left after spending on a pie
= 1 -
16 =
56 The remaining amount is the combined repeated identity. Make the remaining amount the same. LCM of 7 and 6 is 42.
Amount that Bobby had left
=
14 x 48 u
= 12 u
Amount that Bobby spent on balloons
= 35 u - 12 u
= 23 u
23 u = 138
1 u = 138 ÷ 23 = 6
Total amount that Bobby had at first
= 48 u
= 48 x 6
= $288
Answer(s): $288
