A stall was selling flowers.
13 of the earnings are from the sale of 10 daisies and 15 peonies. Of the rest of the earnings,
25 are from the sale of daisies and
35 are from the sale of peonies. Each peony costs four times as much as each daisy. How many flowers were sold?
10 daisies and 15 peonies |
Rest of the earnings |
Total earnings |
1x5 |
2x5 |
|
|
Roses |
Carnations |
|
|
2x2 |
3x2 |
|
5 |
4 |
6 |
15 |
Fraction of the earnings left after the sale of 10 daisies and 15 peonies
= 1 -
13 =
23 The rest of the earnings is repeated. LCM of 2 and 5 is 10.
Cost of 1 daisy = 1 u
Cost of 1 peony = 4 u
Cost of 10 daisies = 10 x 1 u = 10 u
Cost of 15 peonies = 15 x 4 u = 60 u
Total cost of 10 daisies and 15 peonies
= 10 u + 60 u
= 70 u
515 of the earnings → 70 u
115 of the earnings → 70 u ÷ 5 = 14 u
415 of the earnings → 4 x 14 u = 56 u
Number of daisies sold that contributed to the rest of the earnings
= 56 u ÷ 1 u
= 56
615 of the earnings → 6 x 14 u = 84 u
Number of peonies sold that contributed to the rest of the earnings
= 84 u ÷ 4 u
= 21
Number of flowers sold
= 10 + 15 + 56 + 21
= 102
Answer(s): 102