A stall was selling flowers. ¹₄ of the earnings are from the sale of 10 orchids and 10 peonies. Of the rest of the earnings, ³₅ are from the sale of orchids and ²₅ are from the sale of peonies. Each peony costs four times as much as each orchid. How many flowers were sold?

10 orchids and 10 peonies	Rest of the earnings		Total earnings
1x5	3x5
	Roses	Carnations
	3x3	2x3
5	9	6	20

Fraction of the earnings left after the sale of 10 orchids and 10 peonies
= 1 - ¹₄
= ³₄ 

The rest of the earnings is repeated. LCM of 3 and 5 is 15.

Cost of 1 orchid = 1 u
Cost of 1 peony = 4 u

Cost of 10 orchids = 10 x 1 u = 10 u
Cost of 10 peonies = 10 x 4 u = 40 u

Total cost of 10 orchids and 10 peonies
= 10 u + 40 u
= 50 u

⁵₂₀ of the earnings → 50 u 
¹₂₀ of the earnings → 50 u ÷ 5 = 10 u 

⁹₂₀ of the earnings → 9 x 10 u = 90 u 

Number of orchids sold that contributed to the rest of the earnings
= 90 u ÷ 1 u
= 90

⁶₂₀ of the earnings → 6 x 10 u = 60 u

Number of peonies sold that contributed to the rest of the earnings
= 60 u ÷ 4 u
= 15

Number of flowers sold
= 10 + 10 + 90 + 15
= 125

Answer(s): 125