A stall was selling flowers.
16 of the earnings are from the sale of 12 lilies and 10 roses. Of the rest of the earnings,
34 are from the sale of lilies and
14 are from the sale of roses. Each rose costs twice as much as each lily. How many flowers were sold?
12 lilies and 10 roses |
Rest of the earnings |
Total earnings |
1x4 |
5x4 |
|
|
Roses |
Carnations |
|
|
3x5 |
1x5 |
|
4 |
15 |
5 |
24 |
Fraction of the earnings left after the sale of 12 lilies and 10 roses
= 1 -
16 =
56 The rest of the earnings is repeated. LCM of 5 and 4 is 20.
Cost of 1 lily = 1 u
Cost of 1 rose = 2 u
Cost of 12 lilies = 12 x 1 u = 12 u
Cost of 10 roses = 10 x 2 u = 20 u
Total cost of 12 lilies and 10 roses
= 12 u + 20 u
= 32 u
424 of the earnings → 32 u
124 of the earnings → 32 u ÷ 4 = 8 u
1524 of the earnings → 15 x 8 u = 120 u
Number of lilies sold that contributed to the rest of the earnings
= 120 u ÷ 1 u
= 120
524 of the earnings → 5 x 8 u = 40 u
Number of roses sold that contributed to the rest of the earnings
= 40 u ÷ 2 u
= 20
Number of flowers sold
= 12 + 10 + 120 + 20
= 162
Answer(s): 162