A stall was selling flowers.
14 of the earnings are from the sale of 5 peonies and 10 daisies. Of the rest of the earnings,
25 are from the sale of peonies and
35 are from the sale of daisies. Each daisy costs thrice as much as each peony. How many flowers were sold?
5 peonies and 10 daisies |
Rest of the earnings |
Total earnings |
1x5 |
3x5 |
|
|
Roses |
Carnations |
|
|
2x3 |
3x3 |
|
5 |
6 |
9 |
20 |
Fraction of the earnings left after the sale of 5 peonies and 10 daisies
= 1 -
14 =
34 The rest of the earnings is repeated. LCM of 3 and 5 is 15.
Cost of 1 peony = 1 u
Cost of 1 daisy = 3 u
Cost of 5 peonies = 5 x 1 u = 5 u
Cost of 10 daisies = 10 x 3 u = 30 u
Total cost of 5 peonies and 10 daisies
= 5 u + 30 u
= 35 u
520 of the earnings → 35 u
120 of the earnings → 35 u ÷ 5 = 7 u
620 of the earnings → 6 x 7 u = 42 u
Number of peonies sold that contributed to the rest of the earnings
= 42 u ÷ 1 u
= 42
920 of the earnings → 9 x 7 u = 63 u
Number of daisies sold that contributed to the rest of the earnings
= 63 u ÷ 3 u
= 21
Number of flowers sold
= 5 + 10 + 42 + 21
= 78
Answer(s): 78