A stall was selling flowers. ¹₃ of the earnings are from the sale of 8 marigolds and 18 peonies. Of the rest of the earnings, ³₄ are from the sale of marigolds and ¹₄ are from the sale of peonies. Each peony costs four times as much as each marigold. How many flowers were sold?

8 marigolds and 18 peonies	Rest of the earnings		Total earnings
1x2	2x2
	Roses	Carnations
	3x1	1x1
2	3	1	6

Fraction of the earnings left after the sale of 8 marigolds and 18 peonies
= 1 - ¹₃
= ²₃ 

The rest of the earnings is repeated. LCM of 2 and 4 is 4.

Cost of 1 marigold = 1 u
Cost of 1 peony = 4 u

Cost of 8 marigolds = 8 x 1 u = 8 u
Cost of 18 peonies = 18 x 4 u = 72 u

Total cost of 8 marigolds and 18 peonies
= 8 u + 72 u
= 80 u

²₆ of the earnings → 80 u 
¹₆ of the earnings → 80 u ÷ 2 = 40 u 

³₆ of the earnings → 3 x 40 u = 120 u 

Number of marigolds sold that contributed to the rest of the earnings
= 120 u ÷ 1 u
= 120

¹₆ of the earnings → 1 x 40 u = 40 u

Number of peonies sold that contributed to the rest of the earnings
= 40 u ÷ 4 u
= 10

Number of flowers sold
= 8 + 18 + 120 + 10
= 156

Answer(s): 156