A stall was selling flowers. ¹₃ of the earnings are from the sale of 12 orchids and 18 peonies. Of the rest of the earnings, ³₄ are from the sale of orchids and ¹₄ are from the sale of peonies. Each peony costs twice as much as each orchid. How many flowers were sold?

12 orchids and 18 peonies	Rest of the earnings		Total earnings
1x2	2x2
	Roses	Carnations
	3x1	1x1
2	3	1	6

Fraction of the earnings left after the sale of 12 orchids and 18 peonies
= 1 - ¹₃
= ²₃ 

The rest of the earnings is repeated. LCM of 2 and 4 is 4.

Cost of 1 orchid = 1 u
Cost of 1 peony = 2 u

Cost of 12 orchids = 12 x 1 u = 12 u
Cost of 18 peonies = 18 x 2 u = 36 u

Total cost of 12 orchids and 18 peonies
= 12 u + 36 u
= 48 u

²₆ of the earnings → 48 u 
¹₆ of the earnings → 48 u ÷ 2 = 24 u 

³₆ of the earnings → 3 x 24 u = 72 u 

Number of orchids sold that contributed to the rest of the earnings
= 72 u ÷ 1 u
= 72

¹₆ of the earnings → 1 x 24 u = 24 u

Number of peonies sold that contributed to the rest of the earnings
= 24 u ÷ 2 u
= 12

Number of flowers sold
= 12 + 18 + 72 + 12
= 114

Answer(s): 114