A stall was selling flowers.
13 of the earnings are from the sale of 7 carnations and 19 marigolds. Of the rest of the earnings,
23 are from the sale of carnations and
13 are from the sale of marigolds. Each marigold costs twice as much as each carnation. How many flowers were sold?
7 carnations and 19 marigolds |
Rest of the earnings |
Total earnings |
1x3 |
2x3 |
|
|
Roses |
Carnations |
|
|
2x2 |
1x2 |
|
3 |
4 |
2 |
9 |
Fraction of the earnings left after the sale of 7 carnations and 19 marigolds
= 1 -
13 =
23 The rest of the earnings is repeated. LCM of 2 and 3 is 6.
Cost of 1 carnation = 1 u
Cost of 1 marigold = 2 u
Cost of 7 carnations = 7 x 1 u = 7 u
Cost of 19 marigolds = 19 x 2 u = 38 u
Total cost of 7 carnations and 19 marigolds
= 7 u + 38 u
= 45 u
39 of the earnings → 45 u
19 of the earnings → 45 u ÷ 3 = 15 u
49 of the earnings → 4 x 15 u = 60 u
Number of carnations sold that contributed to the rest of the earnings
= 60 u ÷ 1 u
= 60
29 of the earnings → 2 x 15 u = 30 u
Number of marigolds sold that contributed to the rest of the earnings
= 30 u ÷ 2 u
= 15
Number of flowers sold
= 7 + 19 + 60 + 15
= 101
Answer(s): 101