Flynn had some cherry wafers and vanilla wafers.
23 of the number of cherry wafers was equal to
17 of the number of vanilla wafers. After Flynn made 40 more cherry wafers, the number of cherry wafers was
12 of the number of vanilla wafers. How many wafers did he have altogether in the end?
Make the numerators the same. LCM of 2 and 1 is 2.
23 of cherry wafers =
1x27x2 of vanilla wafers
23 of cherry wafers =
214 of vanilla wafers
|
Cherry wafers |
Vanilla wafers |
Total |
Before |
3 u |
14 u |
|
Change |
+ 40 |
|
|
After |
1x7 = 7 u |
2x7 = 14 u |
21 u |
The number of vanilla wafers remains unchanged. Make the number of vanilla wafers the same. LCM of 2 and 14 is 14.
Number of more cherry wafers made
= 7 u - 3 u
= 4 u
4 u = 40
1 u = 40 ÷ 4 = 10
Number of wafers that Flynn had in the end
= 7 u + 14 u
= 21 u
= 21 x 10
= 210
Answer(s): 210