Seth had some vanilla croissants and blueberry croissants. ²₅ of the number of vanilla croissants was equal to ¹₆ of the number of blueberry croissants. After Seth made 26 more vanilla croissants, the number of vanilla croissants was ³₂ of the number of blueberry croissants. How many croissants did he have altogether in the end?
Make the numerators the same. LCM of 2 and 1 is 2.

25 of vanilla croissants = 1x26x2 of blueberry croissants

²₅ of vanilla croissants = ²₁₂ of blueberry croissants

	Vanilla croissants	Blueberry croissants	Total
Before	5 u	12 u
Change	+ 26
After	3x6 = 18 u	2x6 = 12 u	30 u

The number of blueberry croissants remains unchanged.  Make the number of blueberry croissants the same.  LCM of 2 and 12 is 12.

Number of more vanilla croissants made
= 18 u - 5 u
= 13 u

13 u = 26

1 u = 26 ÷ 13 = 2

Number of croissants that Seth had in the end
= 18 u + 12 u
= 30 u
= 30 x 2
= 60

Answer(s): 60