Dylan had some apple croissants and chocolate chip croissants.
59 of the number of apple croissants was equal to
13 of the number of chocolate chip croissants. After Dylan made 21 more apple croissants, the number of apple croissants was
45 of the number of chocolate chip croissants. How many croissants did he have altogether in the end?
Make the numerators the same. LCM of 5 and 1 is 5.
59 of apple croissants =
1x53x5 of chocolate chip croissants
59 of apple croissants =
515 of chocolate chip croissants
|
Apple croissants |
Chocolate chip croissants |
Total |
Before |
9 u |
15 u |
|
Change |
+ 21 |
|
|
After |
4x3 = 12 u |
5x3 = 15 u |
27 u |
The number of chocolate chip croissants remains unchanged. Make the number of chocolate chip croissants the same. LCM of 5 and 15 is 15.
Number of more apple croissants made
= 12 u - 9 u
= 3 u
3 u = 21
1 u = 21 ÷ 3 = 7
Number of croissants that Dylan had in the end
= 12 u + 15 u
= 27 u
= 27 x 7
= 189
Answer(s): 189