Peter had some banana croissants and apricot croissants. ²₅ of the number of banana croissants was equal to ¹₅ of the number of apricot croissants. After Peter made 100 more banana croissants, the number of banana croissants was ³₂ of the number of apricot croissants. How many croissants did he have altogether in the end?
Make the numerators the same. LCM of 2 and 1 is 2.

25 of banana croissants = 1x25x2 of apricot croissants

²₅ of banana croissants = ²₁₀ of apricot croissants

	Banana croissants	Apricot croissants	Total
Before	5 u	10 u
Change	+ 100
After	3x5 = 15 u	2x5 = 10 u	25 u

The number of apricot croissants remains unchanged.  Make the number of apricot croissants the same.  LCM of 2 and 10 is 10.

Number of more banana croissants made
= 15 u - 5 u
= 10 u

10 u = 100

1 u = 100 ÷ 10 = 10

Number of croissants that Peter had in the end
= 15 u + 10 u
= 25 u
= 25 x 10
= 250

Answer(s): 250