Andy had some apricot croissants and cheese croissants. ⁴₇ of the number of apricot croissants was equal to ¹₃ of the number of cheese croissants. After Andy made 6 more apricot croissants, the number of apricot croissants was ³₄ of the number of cheese croissants. How many croissants did he have altogether in the end?
Make the numerators the same. LCM of 4 and 1 is 4.

47 of apricot croissants = 1x43x4 of cheese croissants

⁴₇ of apricot croissants = ⁴₁₂ of cheese croissants

	Apricot croissants	Cheese croissants	Total
Before	7 u	12 u
Change	+ 6
After	3x3 = 9 u	4x3 = 12 u	21 u

The number of cheese croissants remains unchanged.  Make the number of cheese croissants the same.  LCM of 4 and 12 is 12.

Number of more apricot croissants made
= 9 u - 7 u
= 2 u

2 u = 6

1 u = 6 ÷ 2 = 3

Number of croissants that Andy had in the end
= 9 u + 12 u
= 21 u
= 21 x 3
= 63

Answer(s): 63