Xavier had some cranberry croissants and chocolate chip croissants. ²₅ of the number of cranberry croissants was equal to ¹₃ of the number of chocolate chip croissants. After Xavier made 44 more cranberry croissants, the number of cranberry croissants was ³₂ of the number of chocolate chip croissants. How many croissants did he have altogether in the end?
Make the numerators the same. LCM of 2 and 1 is 2.

25 of cranberry croissants = 1x23x2 of chocolate chip croissants

²₅ of cranberry croissants = ²₆ of chocolate chip croissants

	Cranberry croissants	Chocolate chip croissants	Total
Before	5 u	6 u
Change	+ 44
After	3x3 = 9 u	2x3 = 6 u	15 u

The number of chocolate chip croissants remains unchanged.  Make the number of chocolate chip croissants the same.  LCM of 2 and 6 is 6.

Number of more cranberry croissants made
= 9 u - 5 u
= 4 u

4 u = 44

1 u = 44 ÷ 4 = 11

Number of croissants that Xavier had in the end
= 9 u + 6 u
= 15 u
= 15 x 11
= 165

Answer(s): 165