Lee had some cranberry shortbreads and blueberry shortbreads. ⁵₇ of the number of cranberry shortbreads was equal to ¹₈ of the number of blueberry shortbreads. After Lee made 108 more cranberry shortbreads, the number of cranberry shortbreads was ²₅ of the number of blueberry shortbreads. How many shortbreads did he have altogether in the end?
Make the numerators the same. LCM of 5 and 1 is 5.

57 of cranberry shortbreads = 1x58x5 of blueberry shortbreads

⁵₇ of cranberry shortbreads = ⁵₄₀ of blueberry shortbreads

	Cranberry shortbreads	Blueberry shortbreads	Total
Before	7 u	40 u
Change	+ 108
After	2x8 = 16 u	5x8 = 40 u	56 u

The number of blueberry shortbreads remains unchanged.  Make the number of blueberry shortbreads the same.  LCM of 5 and 40 is 40.

Number of more cranberry shortbreads made
= 16 u - 7 u
= 9 u

9 u = 108

1 u = 108 ÷ 9 = 12

Number of shortbreads that Lee had in the end
= 16 u + 40 u
= 56 u
= 56 x 12
= 672

Answer(s): 672