Bobby had $710 more than George at first. Bobby gave $40 to George. As a result, George has
29 as much money as Bobby. How much money had each of them at first?
- Bobby
- George
| |
Bobby |
George |
More |
| Before |
9 u + $40 |
2 u - $40 |
$710 |
| Change |
- $40 |
+ $40 |
|
| After |
9 u |
2 u |
|
(a)
Bobby had $710 more than George at first. If George received another $710, Bobby and George would have the same amount at first.
9 u + 40 = 2 u - 40 + 710
9 u + 40 = 2 u + 670
9 u - 2 u = 670 - 40
7 u = 630
1 u = 630 ÷ 7 = 90
Amount that Bobby had at first
= 9 u + 40
= 9 x 90 + 40
= 810 + 40
= $850
(b)
Amount that George had at first
= 2 u - 40
= 2 x 90 - 40
= 180 - 40
= $140
Answer(s): (a) $850; (b) $140
