Tim had $220 more than Ryan at first. Tim gave $80 to Ryan. As a result, Ryan has
57 as much money as Tim. How much money had each of them at first?
- Tim
- Ryan
| |
Tim |
Ryan |
More |
| Before |
7 u + $80 |
5 u - $80 |
$220 |
| Change |
- $80 |
+ $80 |
|
| After |
7 u |
5 u |
|
(a)
Tim had $220 more than Ryan at first. If Ryan received another $220, Tim and Ryan would have the same amount at first.
7 u + 80 = 5 u - 80 + 220
7 u + 80 = 5 u + 140
7 u - 5 u = 140 - 80
2 u = 60
1 u = 60 ÷ 2 = 30
Amount that Tim had at first
= 7 u + 80
= 7 x 30 + 80
= 210 + 80
= $290
(b)
Amount that Ryan had at first
= 5 u - 80
= 5 x 30 - 80
= 150 - 80
= $70
Answer(s): (a) $290; (b) $70
