Asher had $270 more than Peter at first. Asher gave $60 to Peter. As a result, Peter has
49 as much money as Asher. How much money had each of them at first?
- Asher
- Peter
| |
Asher |
Peter |
More |
| Before |
9 u + $60 |
4 u - $60 |
$270 |
| Change |
- $60 |
+ $60 |
|
| After |
9 u |
4 u |
|
(a)
Asher had $270 more than Peter at first. If Peter received another $270, Asher and Peter would have the same amount at first.
9 u + 60 = 4 u - 60 + 270
9 u + 60 = 4 u + 210
9 u - 4 u = 210 - 60
5 u = 150
1 u = 150 ÷ 5 = 30
Amount that Asher had at first
= 9 u + 60
= 9 x 30 + 60
= 270 + 60
= $330
(b)
Amount that Peter had at first
= 4 u - 60
= 4 x 30 - 60
= 120 - 60
= $60
Answer(s): (a) $330; (b) $60
