Dylan had $460 more than Rael at first. Dylan gave $30 to Rael. As a result, Rael has
27 as much money as Dylan. How much money had each of them at first?
- Dylan
- Rael
| |
Dylan |
Rael |
More |
| Before |
7 u + $30 |
2 u - $30 |
$460 |
| Change |
- $30 |
+ $30 |
|
| After |
7 u |
2 u |
|
(a)
Dylan had $460 more than Rael at first. If Rael received another $460, Dylan and Rael would have the same amount at first.
7 u + 30 = 2 u - 30 + 460
7 u + 30 = 2 u + 430
7 u - 2 u = 430 - 30
5 u = 400
1 u = 400 ÷ 5 = 80
Amount that Dylan had at first
= 7 u + 30
= 7 x 80 + 30
= 560 + 30
= $590
(b)
Amount that Rael had at first
= 2 u - 30
= 2 x 80 - 30
= 160 - 30
= $130
Answer(s): (a) $590; (b) $130
