Justin had $240 more than Sean at first. Justin gave $40 to Sean. As a result, Sean has
57 as much money as Justin. How much money had each of them at first?
- Justin
- Sean
| |
Justin |
Sean |
More |
| Before |
7 u + $40 |
5 u - $40 |
$240 |
| Change |
- $40 |
+ $40 |
|
| After |
7 u |
5 u |
|
(a)
Justin had $240 more than Sean at first. If Sean received another $240, Justin and Sean would have the same amount at first.
7 u + 40 = 5 u - 40 + 240
7 u + 40 = 5 u + 200
7 u - 5 u = 200 - 40
2 u = 160
1 u = 160 ÷ 2 = 80
Amount that Justin had at first
= 7 u + 40
= 7 x 80 + 40
= 560 + 40
= $600
(b)
Amount that Sean had at first
= 5 u - 40
= 5 x 80 - 40
= 400 - 40
= $360
Answer(s): (a) $600; (b) $360
