Peter had $520 more than Seth at first. Peter gave $60 to Seth. As a result, Seth has
49 as much money as Peter. How much money had each of them at first?
- Peter
- Seth
| |
Peter |
Seth |
More |
| Before |
9 u + $60 |
4 u - $60 |
$520 |
| Change |
- $60 |
+ $60 |
|
| After |
9 u |
4 u |
|
(a)
Peter had $520 more than Seth at first. If Seth received another $520, Peter and Seth would have the same amount at first.
9 u + 60 = 4 u - 60 + 520
9 u + 60 = 4 u + 460
9 u - 4 u = 460 - 60
5 u = 400
1 u = 400 ÷ 5 = 80
Amount that Peter had at first
= 9 u + 60
= 9 x 80 + 60
= 720 + 60
= $780
(b)
Amount that Seth had at first
= 4 u - 60
= 4 x 80 - 60
= 320 - 60
= $260
Answer(s): (a) $780; (b) $260
