Henry had $360 more than Ken at first. Henry gave $90 to Ken. As a result, Ken has
58 as much money as Henry. How much money had each of them at first?
- Henry
- Ken
| |
Henry |
Ken |
More |
| Before |
8 u + $90 |
5 u - $90 |
$360 |
| Change |
- $90 |
+ $90 |
|
| After |
8 u |
5 u |
|
(a)
Henry had $360 more than Ken at first. If Ken received another $360, Henry and Ken would have the same amount at first.
8 u + 90 = 5 u - 90 + 360
8 u + 90 = 5 u + 270
8 u - 5 u = 270 - 90
3 u = 180
1 u = 180 ÷ 3 = 60
Amount that Henry had at first
= 8 u + 90
= 8 x 60 + 90
= 480 + 90
= $570
(b)
Amount that Ken had at first
= 5 u - 90
= 5 x 60 - 90
= 300 - 90
= $210
Answer(s): (a) $570; (b) $210
