Cole had $370 more than George at first. Cole gave $10 to George. As a result, George has
49 as much money as Cole. How much money had each of them at first?
- Cole
- George
| |
Cole |
George |
More |
| Before |
9 u + $10 |
4 u - $10 |
$370 |
| Change |
- $10 |
+ $10 |
|
| After |
9 u |
4 u |
|
(a)
Cole had $370 more than George at first. If George received another $370, Cole and George would have the same amount at first.
9 u + 10 = 4 u - 10 + 370
9 u + 10 = 4 u + 360
9 u - 4 u = 360 - 10
5 u = 350
1 u = 350 ÷ 5 = 70
Amount that Cole had at first
= 9 u + 10
= 9 x 70 + 10
= 630 + 10
= $640
(b)
Amount that George had at first
= 4 u - 10
= 4 x 70 - 10
= 280 - 10
= $270
Answer(s): (a) $640; (b) $270
