Neave had $170 more than Brandon at first. Neave gave $10 to Brandon. As a result, Brandon has
58 as much money as Neave. How much money had each of them at first?
- Neave
- Brandon
| |
Neave |
Brandon |
More |
| Before |
8 u + $10 |
5 u - $10 |
$170 |
| Change |
- $10 |
+ $10 |
|
| After |
8 u |
5 u |
|
(a)
Neave had $170 more than Brandon at first. If Brandon received another $170, Neave and Brandon would have the same amount at first.
8 u + 10 = 5 u - 10 + 170
8 u + 10 = 5 u + 160
8 u - 5 u = 160 - 10
3 u = 150
1 u = 150 ÷ 3 = 50
Amount that Neave had at first
= 8 u + 10
= 8 x 50 + 10
= 400 + 10
= $410
(b)
Amount that Brandon had at first
= 5 u - 10
= 5 x 50 - 10
= 250 - 10
= $240
Answer(s): (a) $410; (b) $240
