Paul had $680 more than Charlie at first. Paul gave $60 to Charlie. As a result, Charlie has
310 as much money as Paul. How much money had each of them at first?
- Paul
- Charlie
|
Paul |
Charlie |
More |
Before |
10 u + $60 |
3 u - $60 |
$680 |
Change |
- $60 |
+ $60 |
|
After |
10 u |
3 u |
|
(a)
Paul had $680 more than Charlie at first. If Charlie received another $680, Paul and Charlie would have the same amount at first.
10 u + 60 = 3 u - 60 + 680
10 u + 60 = 3 u + 620
10 u - 3 u = 620 - 60
7 u = 560
1 u = 560 ÷ 7 = 80
Amount that Paul had at first
= 10 u + 60
= 10 x 80 + 60
= 800 + 60
= $860
(b)
Amount that Charlie had at first
= 3 u - 60
= 3 x 80 - 60
= 240 - 60
= $180
Answer(s): (a) $860; (b) $180