George had $140 more than Peter at first. George gave $30 to Peter. As a result, Peter has
57 as much money as George. How much money had each of them at first?
- George
- Peter
| |
George |
Peter |
More |
| Before |
7 u + $30 |
5 u - $30 |
$140 |
| Change |
- $30 |
+ $30 |
|
| After |
7 u |
5 u |
|
(a)
George had $140 more than Peter at first. If Peter received another $140, George and Peter would have the same amount at first.
7 u + 30 = 5 u - 30 + 140
7 u + 30 = 5 u + 110
7 u - 5 u = 110 - 30
2 u = 80
1 u = 80 ÷ 2 = 40
Amount that George had at first
= 7 u + 30
= 7 x 40 + 30
= 280 + 30
= $310
(b)
Amount that Peter had at first
= 5 u - 30
= 5 x 40 - 30
= 200 - 30
= $170
Answer(s): (a) $310; (b) $170
