Tommy had $320 more than Howard at first. Tommy gave $60 to Howard. As a result, Howard has
57 as much money as Tommy. How much money had each of them at first?
- Tommy
- Howard
| |
Tommy |
Howard |
More |
| Before |
7 u + $60 |
5 u - $60 |
$320 |
| Change |
- $60 |
+ $60 |
|
| After |
7 u |
5 u |
|
(a)
Tommy had $320 more than Howard at first. If Howard received another $320, Tommy and Howard would have the same amount at first.
7 u + 60 = 5 u - 60 + 320
7 u + 60 = 5 u + 260
7 u - 5 u = 260 - 60
2 u = 200
1 u = 200 ÷ 2 = 100
Amount that Tommy had at first
= 7 u + 60
= 7 x 100 + 60
= 700 + 60
= $760
(b)
Amount that Howard had at first
= 5 u - 60
= 5 x 100 - 60
= 500 - 60
= $440
Answer(s): (a) $760; (b) $440
