Rael had $40 more than Liam at first. Rael gave $10 to Liam. As a result, Liam has
57 as much money as Rael. How much money had each of them at first?
- Rael
- Liam
| |
Rael |
Liam |
More |
| Before |
7 u + $10 |
5 u - $10 |
$40 |
| Change |
- $10 |
+ $10 |
|
| After |
7 u |
5 u |
|
(a)
Rael had $40 more than Liam at first. If Liam received another $40, Rael and Liam would have the same amount at first.
7 u + 10 = 5 u - 10 + 40
7 u + 10 = 5 u + 30
7 u - 5 u = 30 - 10
2 u = 20
1 u = 20 ÷ 2 = 10
Amount that Rael had at first
= 7 u + 10
= 7 x 10 + 10
= 70 + 10
= $80
(b)
Amount that Liam had at first
= 5 u - 10
= 5 x 10 - 10
= 50 - 10
= $40
Answer(s): (a) $80; (b) $40
