Michael had $830 more than Simon at first. Michael gave $100 to Simon. As a result, Simon has
29 as much money as Michael. How much money had each of them at first?
- Michael
- Simon
| |
Michael |
Simon |
More |
| Before |
9 u + $100 |
2 u - $100 |
$830 |
| Change |
- $100 |
+ $100 |
|
| After |
9 u |
2 u |
|
(a)
Michael had $830 more than Simon at first. If Simon received another $830, Michael and Simon would have the same amount at first.
9 u + 100 = 2 u - 100 + 830
9 u + 100 = 2 u + 730
9 u - 2 u = 730 - 100
7 u = 630
1 u = 630 ÷ 7 = 90
Amount that Michael had at first
= 9 u + 100
= 9 x 90 + 100
= 810 + 100
= $910
(b)
Amount that Simon had at first
= 2 u - 100
= 2 x 90 - 100
= 180 - 100
= $80
Answer(s): (a) $910; (b) $80
