Tina and Marion used the same number of longans to bake cakes. Tina used
37 of her longans and Marion used
45 of her longans. They had a total of 301 longans at first.
- How many longans did each girl use?
- How many longans did both girls have left altogether?
| |
Tina |
Marion |
Total |
Before |
7x4 =
28 u |
5x3 =
15 u |
43 u |
Change |
- 3x4 =
- 12 u |
- 4x3 =
- 12 u |
|
After |
4x4 =
16 u |
1x3 =
3 u |
19 u |
(a)
Tina and Marion used the same number of longans to bake cakes. Make the numerators the same. LCM of 3 and 4 is 12.
3x47x4 of Mary's longans =
4x35x3 of Marion's longans
1228 of Mary's longans =
1215 of Marion's longans
Total number of longans at first
= 28 u + 15 u
= 43 u
43 u = 301
1 u = 301 ÷ 43 = 7
Number of longans that each girl used
= 12 u
= 12 x 7
= 84
(b)
Total number of longans that both girls had left
= 16 u + 3 u
= 19 u
= 19 x 7
= 133
Answer(s): (a) 84; (b) 133
