Kimberly and Jen used the same number of longans to bake cakes. Kimberly used
57 of her longans and Jen used
27 of her longans. They had a total of 343 longans at first.
- How many longans did each girl use?
- How many longans did both girls have left altogether?
| |
Kimberly |
Jen |
Total |
Before |
7x2 =
14 u |
7x5 =
35 u |
49 u |
Change |
- 5x2 =
- 10 u |
- 2x5 =
- 10 u |
|
After |
2x2 =
4 u |
5x5 =
25 u |
29 u |
(a)
Kimberly and Jen used the same number of longans to bake cakes. Make the numerators the same. LCM of 5 and 2 is 10.
5x27x2 of Mary's longans =
2x57x5 of Jen's longans
1014 of Mary's longans =
1035 of Jen's longans
Total number of longans at first
= 14 u + 35 u
= 49 u
49 u = 343
1 u = 343 ÷ 49 = 7
Number of longans that each girl used
= 10 u
= 10 x 7
= 70
(b)
Total number of longans that both girls had left
= 4 u + 25 u
= 29 u
= 29 x 7
= 203
Answer(s): (a) 70; (b) 203
