Simon, Will and Billy had 160 coins. After Simon used 23 coins and Will used
35 of her coins, Simon had twice as many coins left as Will. Billy bought another 33 coins, he had four times the number of coins Will had left. How many coins did Billy have at first?
| |
Simon |
Will |
Billy |
Total |
| Before |
4 u + 23 |
5 u |
8 u - 33 |
160 |
| Change |
- 23 |
- 3 u |
+ 33 |
|
| After |
4 u |
2 u |
8 u |
|
Comparing Simon
and Will in the end |
2 |
1 |
|
|
Comparing Billy
and Will in the end |
|
1 |
4 |
|
Number of coins that Simon had in the end
= 2 x 2 u
= 4 u
Number of coins that Billy had in the end
= 4 x 2 u
= 8 u
Total number of coins at first
= 4 u + 23 + 5 u + 8 u - 33
= 17 u - 10
17 u - 10 = 160
17 u = 160 + 10
17 u = 170
1 u = 170 ÷ 17 = 10
Number of coins that Billy had at first
= 8 u - 33
= 8 x 10 - 33
= 80 - 33
= 47
Answer(s): 47
