Bobby, Dylan and Ben had 140 coins. After Bobby used 22 coins and Dylan used
58 of her coins, Bobby had thrice as many coins left as Dylan. Ben bought another 27 coins, he had four times the number of coins Dylan had left. How many coins did Ben have at first?
| |
Bobby |
Dylan |
Ben |
Total |
| Before |
9 u + 22 |
8 u |
12 u - 27 |
140 |
| Change |
- 22 |
- 5 u |
+ 27 |
|
| After |
9 u |
3 u |
12 u |
|
Comparing Bobby
and Dylan in the end |
3 |
1 |
|
|
Comparing Ben
and Dylan in the end |
|
1 |
4 |
|
Number of coins that Bobby had in the end
= 3 x 3 u
= 9 u
Number of coins that Ben had in the end
= 4 x 3 u
= 12 u
Total number of coins at first
= 9 u + 22 + 8 u + 12 u - 27
= 29 u - 5
29 u - 5 = 140
29 u = 140 + 5
29 u = 145
1 u = 145 ÷ 29 = 5
Number of coins that Ben had at first
= 12 u - 27
= 12 x 5 - 27
= 60 - 27
= 33
Answer(s): 33
