Paul, Albert and Liam had 256 pencils. After Paul used 16 pencils and Albert used
15 of her pencils, Paul had four times as many pencils left as Albert. Liam bought another 24 pencils, he had thrice the number of pencils Albert had left. How many pencils did Liam have at first?
| |
Paul |
Albert |
Liam |
Total |
| Before |
16 u + 16 |
5 u |
12 u - 24 |
256 |
| Change |
- 16 |
- 1 u |
+ 24 |
|
| After |
16 u |
4 u |
12 u |
|
Comparing Paul
and Albert in the end |
4 |
1 |
|
|
Comparing Liam
and Albert in the end |
|
1 |
3 |
|
Number of pencils that Paul had in the end
= 4 x 4 u
= 16 u
Number of pencils that Liam had in the end
= 3 x 4 u
= 12 u
Total number of pencils at first
= 16 u + 16 + 5 u + 12 u - 24
= 33 u - 8
33 u - 8 = 256
33 u = 256 + 8
33 u = 264
1 u = 264 ÷ 33 = 8
Number of pencils that Liam had at first
= 12 u - 24
= 12 x 8 - 24
= 96 - 24
= 72
Answer(s): 72
